Question

Aaron, Ben, and Charles shared 110 marbles. Ben Received twice as many marbles as Aaron. Charles received 10 marbles more than Aaron. How many marbles did each boy receive?
(This is algebra) Please SHOW work!

Answer 1

Step-by-step explanation:

let Aaron get x marbels

so

Ben = 2x

Charles = x + 10

according to the question

x + 2x + (x+10) = 110

=> x + 2x + x + 10 = 110

=> 4x + 10 = 110

=> 4x = 110 - 10

=> 4x = 100

=> x = 100/4

=> x = 25

so

Aaron = x = 25 marbels

Ben = 2x = 25 × 2 = 50 marbels

Charles = x + 10 = 25 + 10 = 35 marbels

Answer 2

Answer:

Aaron = 25

Ben = 50

Charles = 35

Step-by-step explanation:

Let Aaron have x marbels.

Since Ben recieved twice as marbles as Aaron, Ben has 2x marbles.

Charles recieved 10 marbles more than Aaron, thus Charles has (x + 10) marbles.

We know, that they all together share 110 marbles,

which means $x+2x+(x+10)=110$

Solving,

$4x+10=110$

$4x=110-10=100$

$x=\frac{100}{4}$

$x=25$

Thus, Aaoron recieves 25 (i.e x) marbles, Ben recieves 50 (i.e 2x) marbles and Charles recieved 35 (i.e x + 10) marbles.