Math, asked by AhitaR, 19 days ago

(ab^2) × (-b^2c) × (-a^2c^3) × (-3abc)
(a b ^ 2) \times (- b ^ 2c)  \times (- a ^ 2c ^ 3) \times (- 3abc)

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Answered by 5867
1

Answer:

sorry

Step-by-step explanation:

this is your answer the second problem I could not do

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