AB = 200 cm: 2.4 m², cal
Foto Tio 15 24. ABCD is a parallelogram. DE I AB. If
m AD = 130 cm and area of the
parallelogram is 2.4 m², calculate:
(a) AE
(b) EB.
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Answer:
ANSWER
Here,given
a=1
d=4−1=3
and,s
n
=287
Now,
s
n
=
2
n
(2a+(n−1)d)
⇒287=
2
n
(2×1+(n−1)3)
⇒287=
2
n
(2+3n−3)
⇒574=n(3n−1)
⇒574=3n
2
−n
⇒3n
2
−n−574=0
onsolvingthequadraticequatonusingformula
n=
2a
−b±
b
2
−4ac
Wegetn=14&
3
−41
[doesnotexist]
so,n=14
Now,
s
n
=
2
n
(a+1)
⇒287=
2
14
(1+x)
⇒574=14(1+x)
⇒(1+x)=
14
574
⇒1+x=41
⇒x=41−1
∴x=40
x=40isthesolution.
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