Question

AB= 3x, BC= 3x/2. Find AC by pythagoras theorem.
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Answer 1

Answer:

AC by pythagoras theorem

AB= 3x, BC= 3x/2

$ac = \sqrt{ {(ab)}^{2} + ( {bc)}^{2} } \\ ac = \sqrt{9 {x}^{2} + \frac{9}{4} {x}^{2} } \\ ac = \frac{3}{2} x\sqrt{5}$