Question

is the ecceleration deu to gravity "g" same everywhere on surface of the earth explain how "g" varies with altitude and latitude​

Answer 1

Answer:

The value of g at all place is not the same, it varies. The value of g is more at the poles and less at the equator. Hence on the basis of altitude the value of g changes.

Answer 2

Answer:

Variation of g with altitude, depth and latitude

Consider an object of mass m at a height h from the surface of the Earth. Acceleration experienced by the object due to Earth is

g'=GM'/(Re-d)

$g'=GM/ {(Re+h)}^{2}$

Variation of g with depth:

Consider a particle of mass m which is in a deep mine on the Earth. (Example: coal mines in Neyveli). Assume the depth of the mine as d. To calculate g′ at a depth d, consider the following points.

The part of the Earth which is above the radius (Re − d) do not contribute to the acceleration. The result is proved earlier and is given as

$g'=GM'/ {(Re-d)}^{2}$

Here M ’ is the mass of the Earth of radius (Re-d).