Question

√Ab / A+b = 6 can anyone solve this equation please..

Answer 1

√Ab =  6 (A+b)

Ab = 36 (A² + b² + 2 Ab)
36 A² + 71 A b + 36 b² = 0
Let   A/b =  x

so   36 x² +  71 x + 36 = 0
           x = [ -71 +- √(71² - 4*36²) ]/2

A + b =  1/6 * √Ab   --- (1)
(A - b)² = (A + b)² - 4 a b 
            = Ab/36  - 4 a b
            = - 143 A b/36       --- (2)
A - b   = + √(-143Ab) /6       or    - √(-143 Ab) /6      --- (3)

If  Ab is positive then  (1) is valid, but (3) is not valid.  If  Ab is negative, then (1) is not valid,  but (2) is valid.

There are no real solutions to the given problem. Only complex number solutions exist.