Question

ab(a-b) + bc (b-c) + Ca(c-a) is equal to​

Answer 1

Answer:

equal to A^2 B- AB^2 + B^2 C- BC^2 + C^2 A - CA^2 ( expanding or opening brackets)

Answer 2

Answer:

Step-by-step explanation:

ab(a-b) + bc (b-c) + Ca(c-a)

=a2b−ab2+b2c−bc2+ac2−a2c

Factor: a2(b−c)−a(b2−c2)+bc(b−c)

=a2(b−x)−a(b−c)(b+c)+bc(b−c)

=(b−c)[a2−a(b+c)+bc]

=(b−c)[a2−ab−ac+bc]  

=(b−c)[a(a−b)−c(a−b)]

=(b−c)(a−b)(a−c)