Question

(x³+7x²-x)/x²+6x-7=?
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Answer 1

Answer:

x3+7x2−x+16=x3−x2+8x2−8x+7x−7+23

=x2(x−1)+8x(x−1)+7(x−1)+23=(x−1)(x2+8x+7)+23

=(x−1)(x+1)(x+7)+23=2i.(2+2i)=2(1+i).(8+2i)=2(4+i)+23

=8i.(1+i).(4+i)+23=8i.(i2+5i+4)+23

=8i.(−1+5i+4)+23=8i.(5i+3)+23

=40i2+24i+23=−40+24i+23=−17+24i

Ans: −17+24i