AB=AC and A ARC
95
asosceles
In SABC the disector AD show that
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Given in ΔABC, the bisector AD of ∠A is perpendicular to side BC.
In ΔBAD and ΔCAD,
∠BAD=∠CAD ....Given
∠ADB=∠ADC=90
0
.........(AD is perpendicular to side BC)
AD=AD.............(Common side)
∴ΔBAD≅ΔCAD ........[ASA test]
∴AB=AC ...........[CSCT]
By converse of isosceles triangle theorem,
∴△ABC is isosceles. [henceproved]
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