AB=ACin triangle ABC. if angle A= 50. find Angle B and angle C
ak610:
65 degree is the answer
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angle AB = AC = 75°
BECAUSE SIDES ARE EQUAL....
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AB=AC
ANGLE b=ANGLE c(opposite angel will be equal)
so,let both the angles to be X
#sum of all the ANGLES in a ∆ is 180°
so,
ANGLE a + ANGLE b + ANGLE c=180°
50°+X+X=180°
2X=130°
X=65°
angle b=65°
angle c=65°
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