AB &CD are two equal angle of center of circle show that AB=CD
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Given: AB and CD are the chords of a circle whose centre is O.
They intersect at P. PO is bisector of angle APD.
Prove: AB=CD
Construction: Draw OR perpendicular AB and OQ perpendi cular CD
Proof: In∆ OPR and ∆OPQ
AngleOPR= AngleOPQ (given)
OP=OP (common)
angleORP= angleOQP (construction)
∆OPR congurent ∆OPQ (AAS axiom)
OR= OQ (C.P.CT)
AB= CD (chords of a circle which are at equidistant from the centre are equal).
Hence, Proved.
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