Question

AB and ac are two chords of circle which are perpendicular to each other if ab=4cm and ac =3cm then find the length of the radius of the circle ?​

Answer 1

Step-by-step explanation:

In right angled triangle BAC

BC^2=AB^2+AC^2

(2r)^2=(4)^2+(3)^3

4r^2=16+9=25

r^2=25/4

r = 5/2 cm. or 2.5 cm

Answer 2

Step-by-step explanation:

AB and AC are perpendicular to each other ∠BAC=90∘,∴ΔABC∠BAC=90∘,∴ΔABC is a right- angled triangle of which BC is hypotetnuse.

∴BC2=AB2+AC2∴BC2=AB2+AC2 [ by pythagors theorem] =42+32=16+9=25=42+32=16+9=25

∴BC25−−√=5∴BC25=5

Now, BC is one of the diamters of the circle.

∴∴ radius of the circle 52cm=2.5cm52cm=2.5cm