AB and BC are two chords of a circle whose center is o such that angle oab = angle ocb prove that ab=bc
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Let ABO be x
BO=AOL (radius)
=>ABO=BAO=x
BO=CO (RADIUS)
=>OBC=OCB=x
BOA=180-x-x
BOC=180-x-x
:.BOA=BOC
=>AB=BC (equal chords sub tend equal angles)
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Let ABO be x
BO=AOL (radius)
=>ABO=BAO=x
BO=CO (RADIUS)
=>OBC=OCB=x
BOA=180-x-x
BOC=180-x-x
:.BOA=BOC
=>AB=BC (equal chords sub tend equal angles)
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