Question

AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see Fig. 7.50). Show that ∠ A > ∠ C and ∠ B > ∠ D.

Answer 1

Answer:

hence proof that a is greater than b and the c is greater than d

$| < { {52.0.. \times \frac{5}{?} }^{?} }^{?} | \times \frac{0}.1 \: thamj \: k$

Answer 2

Hope it helps uh! ❤️

Plss! Mark me the brainliestt!