Question

AB and CD are two chords of a circle on the same
side of the centre such that AB = 8 cm, CD = 10 cm
and AB || CD. If the distance between AB and CD
is 2 cm, then find the radius of the circle.

Answer 1

Step-by-step explanation:

Let ON = x

On rt ΔOMC

OB

2

=OM

2

+MB

2

=(17−x)

2

+5

2

....(i)

In rt. ΔOND,

OD

2

=ON

2

+ND

2

=x

2

+12

2

....(ii)

But OB

2

=OD

2

[∵ OB and OD being the radii of the same circle are equal]

∴x

2

+12

2

=(17−x)

2

+5

2

⇒x

2

+144=289+x

2

−34x+25

⇒34x=289+25−144=170

⇒x=

34

170

=5

Hence from (2)

OD

2

=5

2

+12

2

=25+144

=169=13

2

∴OD=13

Hence the radius of the circle is 13 cm.

Answer 2

Answer:

good morning sir can I am ..........