AB and CD are two chords of a circle such that AB=6cm, CD=12cm and ABllCD. If the distance between AB and CD is 3cm, find the radius of the circle.
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3√5. by using Pythagoras theorem
r²=x²+36>>>equation 1.
In right angle OPB =r²=(x+3)²+3²
By Pythagoras theorem,
r²=x²+6x+9+9=x²+6x+18>>>>equation 2.
From equ 1 and 2
we get x²+36=x²+6x+18
6x=18 x=18/6 =3
put x=3 in equ 1,
r²=3²+36=9+36=45
r=√45
= 3√5.......
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