Question

AB and CD are two chords of a circle which intersect each other externally at P. If AB=4 cm, BP = 5 cm, PD = 3 cm, then the length of CD is

Answer 1

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Answer 2

Answer:

$CD = 12 \:cm$

Step-by-step explanation:

Here ,two chords AB and CD , when produced , meet at a point P.

=> PA × PB = PC × PD

=> (PB+AB) × PB = (PD+CD)×PD

=> (5+4)×5 = (3+CD)× 3

=> 9 × 5 = (3+CD) × 3

$\implies \frac{9\times 5}{3} = 3+CD$

$\implies 15 = 3+CD$

$\implies 15-3 = CD$

$\implies CD = 12\:cm$

Therefore,

$CD = 12 \:cm$

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