Question

AB and CD are two parallel chords of lenghts 8cm and 6cm respectively. if they are 1cm apart and lie on the same side of the centre find the distance of CD from centre. plz it's urgent​

Answer 1

Answer:

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Answer 2

Let AB and CD are two parallel chords of a circle having length 6 cm and 8 cm and radius is O.

Let radius of the circle is r cm.

Now draw OP perpendicular to AB and OQ perpendicular to CD.

since OP is perpendicular to AB and OQ is perpendicular to CD and AB || Cd

So points O, P and Q are collinear.

From figure, OP = 4.

P, Q are the mid points of AB and CD.

So AP = PB = AB/2 = 6/2 = 3

CQ = QD = CD/2 = 8/2 = 4

Now in ΔOAP

OA2 = OP2 + AP2

=> r2 = 42 + 32

=> r2 = 16 + 9

=> r2 = 25

=> r = √25

=> r = 5