AB and CD intersect each other at point 0.Measure of one angle is 56°, then find measure of other three angles.
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2nd angle= 56° vertically opposite angles
3rd angle= 180-56°=124°
4th angle= 124° verically opposite to 3rd angle
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AB is CD is intersecting each other
at point ' O '
i ) <COB = <AOD = 56°
[ Vertically opposite angles ]
ii ) <COA + <AOD = 180°
[ Linear pair ]
=> <COA = 180° - <AOD
=> <COA = 180° - 56°
= 124°
Now ,
<BOD = <COA = 124°
[ vertically opposite angles ]
Therefore ,
<COB = 56° ,
<COA = <BOD = 124°
••••
at point ' O '
i ) <COB = <AOD = 56°
[ Vertically opposite angles ]
ii ) <COA + <AOD = 180°
[ Linear pair ]
=> <COA = 180° - <AOD
=> <COA = 180° - 56°
= 124°
Now ,
<BOD = <COA = 124°
[ vertically opposite angles ]
Therefore ,
<COB = 56° ,
<COA = <BOD = 124°
••••
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