Question

(ab - bc)^2+2ab^2c
simply the following ?
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Answer 1

Given, (ab+bc) ²−2ab2c.

We know,

(a+b)²=a²+2ab+b²

Then,

(ab+bc)² −2ab²c

=(ab) ²+2(ab)(bc)+(bc)² −2ab²c

=a²b²+2ab²c+b²c²−2ab²c

=a²+b²+b²+c²

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