Question

(ab+bc)(ab-bc) +(bc+ca)+(bc-ca) +(ca+ab)(ca-ab) ​

Answer 1

Step-by-step explanation:

(ab)^2-(bc)^2+bc+ca+bc-ca+(ca)^2-(ab)^2

=a^2b^2-b^2c^2+2bc+c^2a^2-a^2b^2

=c^2a^2-b^2c^2+2bc

Answer 2

Answer:

Step-by-step explanation:

ab-bc,bc-ca,ca-ab is 0