ab- bc, bc - ca,ca- ab
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Answered by
2
Answer:
=0
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Answered by
11
Answer:
1. ab-bc,bc-ca,ca-ab
= (ab-bc)+(bc-ca)+(ca-ab)
= ab-bc+bc-ca+ca-ab
= ab-ba-bc+bc-ca+ca
= 0
Hope it helps you dear✌✌
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