Math, asked by rahul264139, 10 months ago

ab-bc , bc-ca, ca-ab

Answers

Answered by Anonymous

12

Answer:

1. (ab-bc)+(bc-ca)+(ca-ab)

= ab-bc-bc-ca+ca-ab

= ab-ba-bc+bc-ca+ca

= 0

Hope it helps you dear✌✌

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