Math, asked by laxmivenkat782, 1 month ago

ab(c²+d²)-a²cd–b²cd​

Answers

Answered by yachumaro
0

Answer:

ab (c2 + d2) – a2cd – b2cd

= abc2 + abd2 – a2cd – b2cd

= abc2 – a2cd – b2cd + abd2

= ac (bc – ad) – bd (bc – ad)

= (bc – ad) (ac – bd)

Answered by khusboo1237
4

Answer:

(bc-ad) ( ac-bd )

Step-by-step explanation:

abc2 + abd2 – a2cd – b2cd

= abc2 – a2cd – b2cd + abd2

= ac (bc – ad) – bd (bc – ad)

= (bc – ad) (ac – bd)

hooope it helps you

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