(AB + CB) × 4 = 520, where A, B and C are positive integers, then Value of B can be
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Answer:
Answer
a
b
=
b
c
=(integer)
b
2
=ac⇒c=
a
b
2
3
a+b+c
=b+2
a+b+c=3b+6⇒a−2b+c=6
a−2b+
a
b
2
=6⇒1−
a
2b
+
a
2
b
2
=
a
6
(
a
b
−1)
2
=
a
6
⇒a=6 only
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