AB||CD AND ANGLE F =30 DEGREES. FIND ANGLE ECD
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36
in AFE
angle AEF =180-(90+30)=180-120=60
then angle CEB=60(vertically opposite angle)
angle CEB + angle ECD=180(same side of traversal line)
then, angle ECD=180-60=120
angle AEF =180-(90+30)=180-120=60
then angle CEB=60(vertically opposite angle)
angle CEB + angle ECD=180(same side of traversal line)
then, angle ECD=180-60=120
Answered by
3
Answer:
ECD= 120
Step-by-step explanation
FEB=AFE+FAE (exterior angle property)
FEB=30+90=120
FEB=ECD (corresponding angles)
ECD= 120
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