Question

AB||CD, angle APQ=50° & angle PRD=127° then, find the x and y......
.please.

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Answer 1

Step-by-step explanation:

x = 50 alternate angle

y = 180-(50+53)

53 bcz 180-127. as its linear pair

Answer 2

let angle PRQ be z

z = 180 - 127 (linear pair)

z = 53°

x = 50° (alternate angle)

x + z + y = 180° (angle sum property of a ∆)

50° + 53° + y = 180°

103° + y = 180°

y = 180-103°

y = 77° ans.