Question

Ab||cd, angleAPQ = x+20 and angleDQP =3x-60. Find x

Answer 1

x+20=3x-60
x-3x=-60-20
-2x=-80
x=-80/-2
x=40

Answer 2

Solution:

⇒$x+20=3x-60$   (alternate interior angles are equal)

⇒$20+60=3x-x$

⇒$80=2x$

⇒$x=\frac{80}{20}$

⇒$x=40$