Question

AB||CD , CD||EF and ×:y =3:2 find z​

Answer 1

$\bf\large\underline\pink{Solution:-}$

Given x:y=3:2

AB//CD//EF

so x and y are co interior angles

i.e. x+y=180

3z+2z=180 (given 3:2)

5z=180

z=180÷5=36

so x=3×36=108 and 2×36=72.

Now x=z (alternate interior angles)

108 degree(ans)

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Answer 2

$\huge\purple{Answer:-}$

Given x:y=3:2

AB//CD//EF

so x and y are co interior angles

i.e. x+y=180

3z+2z=180 (given 3:2)

5z=180

z=180÷5=36

so x=3×36=108 and 2×36=72.

Now x=z (alternate interior angles)

108 degree(ans)