Question

AB||CD If, angle 2=(2x+30), angle 4= (x+2y) angle 6= (3y+10) find angle 5...pls answer asap​

Answer 1

Answer:

hope it helps you..

pls mark it as brainliest

Step-by-step explanation:

$angle 6 = (3y + 10) \\ thus \\ (3y + 10) + angle5 = 180..........(angles \: in \: linear \: pair) \\3y + 10 + angle5 = 180 \\ 3y + angle5 = 180 - 10 \\ 3y + angle5 = 170 \\ y + angle5 = \frac{170}{3} \\ y + angle5 = 56.66666 \\ thus \: approxiamately \: 56.7degree$