AB
CD is a cyclic quadrilateral find the angles of a cyclic quadrilateral
Attachments:
Answers
Answered by
4
In a cyclic quadrilateral, opposite angles are supplementary
thus angle A+angleC=180°
=>4y+20-4x=180
=>4y-4x=160
=>y-x=40-----1
and similarly
angle B+angleD=180
=>3y-5-7x+5=180
=>3y-7x=180------2
*see the solve in the pic *
we get x=-15 and y=25
now put values of X and y
angle A=4y+20=4*25+20=120°
angle B=3y-5=3*25-5=75-5=70°
angle C=-4x=-4(-15)=60°
angle D=-7x+5=-7(-15)+5=105+5=110°
thus angle A+angleC=180°
=>4y+20-4x=180
=>4y-4x=160
=>y-x=40-----1
and similarly
angle B+angleD=180
=>3y-5-7x+5=180
=>3y-7x=180------2
*see the solve in the pic *
we get x=-15 and y=25
now put values of X and y
angle A=4y+20=4*25+20=120°
angle B=3y-5=3*25-5=75-5=70°
angle C=-4x=-4(-15)=60°
angle D=-7x+5=-7(-15)+5=105+5=110°
Attachments:
Answered by
0
Answer:
hope this helps u...
mark me as brainlist...
Attachments:
Similar questions