Question

AB=CD
<ABD=80
<ACD=20
FIND <ADB​

Answer 1

∠ADB = 40°

Step-by-step explanation:

Correction AD = CD

∠ABD = 80°

=> ∠ABC = 80°

∠ACD = 20°

=> ∠ACB = 20°

∠ABC + ∠ACB + ∠BAC = 180° ( Sum of angles of triangle)

=> 80° + 20° + ∠BAC = 180°

=>  ∠BAC = 80°

AD = CD

=> ∠ACD = ∠CAD = 20°

∠BAC = ∠BAD + ∠CAD

=> 80° = ∠BAD + 20°

=> ∠BAD = 60°

∠ABD + ∠BAD + ∠ADB = 180°

=> 80° + 60° + ∠ADB = 180°

=> ∠ADB = 40°

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