Question

A person goes from A to B with a uniform speed of 8 km/h and comes back with a uniform speed of 12 km/h in 10 hrs, then what is the distance between A and B?

Answer 1

A person goes from A to B with a uniform speed of 8 km/h and comes back with a uniform speed of 12 km/h

Find average speed:

$V_{av} = \frac{2 v_1 v_2}{v_1+v_2} \\ \\ V_{av} = \frac{2 \times 8 \times 12}{8 + 12} \\ \\ V_{av} = \frac{2 \times 8 \times 12}{20} \\ \\ V_{av} = 9.6 \: kmph$

Time taken from A to B = 10/2 = 5 hours

Distance between A and B= Vav × t = 9.6 × 5 = 48 km

Answer 2

❖ ── ✦ ──『✙』── ✦ ── ❖I have explained the answer below
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ᴀ ᴘᴇʀsᴏɴ ɢᴏᴇs ғʀᴏᴍ ᴀ ᴛᴏ ʙ ᴡɪᴛʜ ᴀ ᴜɴɪғᴏʀᴍ sᴘᴇᴇᴅ ᴏғ 8 ᴋᴍ/ʜ ᴀɴᴅ ᴄᴏᴍᴇs ʙᴀᴄᴋ ᴡɪᴛʜ ᴀ ᴜɴɪғᴏʀᴍ sᴘᴇᴇᴅ ᴏғ 12 ᴋᴍ/ʜ

ғɪɴᴅ ᴀᴠᴇʀᴀɢᴇ sᴘᴇᴇᴅ: --

Average velocity=2×v1×v2/v1+v2

=2×8×12/8+12

=2×8×12/20

=9.6 km/h

ᴛɪᴍᴇ ᴛᴀᴋᴇɴ ғʀᴏᴍ ᴀ ᴛᴏ ʙ = 10/2 = 5 ʜᴏᴜʀs

ᴅɪsᴛᴀɴᴄᴇ ʙᴇᴛᴡᴇᴇɴ ᴀ ᴀɴᴅ ʙ= ᴠᴀᴠ × ᴛ = 9.6 × 5 = 48 ᴋᴍ