Question

manu went to his maths teacher and asked" sir i want some chocolate to distribute can u please provide then the teacher said" i am giving u two numbers 1/3+2√2 and 1/3-2√2 if u can find the value of sum of their square, then i will provide u chocolates as the resulting value of sum of square of given number. find no of chocolates .
PLEASE READ NUMBERS AND ANSWER........

Answer 1

first number is 1 / 3+2√2

it's square is , ( 1 / 3+2√2 ) ^2

= 1 / 9 + 8 + 12√2

= 1 / 17 + 12√2


second number is 1 / 3 - 2√2

it's square is , ( 1 / 3 - 2√2 ) ^2

= 1 / 9 + 8 - 12√2

= 1 / 17 - 12√2

sum of these two is ,

= 1 / 17 + 12√2 + 1 / 17 - 12√2

= 17 - 12√2 + 17 + 12√2 / (17^2 - (12√2)^2)

= 34 / 289 - 288

= 34 /1

= 34

so chocolates must be 34