Ab crystallizes in a bcc with edge length a equal to 387pm the distance between two oppositively charged ions in the lattice is. solution
Answers
Answered by
2
The distance b/w them would be ;
2r = root(3)*a/2
2r => 387*root3/2 => 335 pm approx.
This would be the distance b/w the two opposite charges.
2r = root(3)*a/2
2r => 387*root3/2 => 335 pm approx.
This would be the distance b/w the two opposite charges.
Similar questions