AB II CD In the ginen fig, if angle BAE =105 angle AEC=25 then find nd the value of angle x.
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From E, draw EF||AB||CD. Now, EF∣∣CD and CE is the transversal. ∴ [co. int. angles] implies x^(@)+angleCEF=180^(@) implies angleCEF=(180^(@)-x^(@)). Again, EF||AB and AE is the transversal. :. angleBAE+angleAEF=180^(@) [co. int. angles] implies 105^(@)+angleAEC+angleCEF=180^(@) implies 105^(@)+25^(@)+(180^(@)-x^(@))=180^(@) =x^(@)=130^(@). Hence, x=130.Read more on Sarthaks.com - https://www.sarthaks.com/1137977/in-the-given-figure-ab-cd-angleeab-105-angleaec-25-and-angleecd-x-find-the-value-of-x?show=1138277#a1138277
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105+25 = 130
180-130=50
50 is the correct Answer
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