ab is a chord of a circle with centre o. at b a tangent pb is drawn such that its length is 24cm. the distance of p from the centre is 26 cm if the chord ab=16cm find its distance from the centre.
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According to question
Length of Chord ab = 16 Cm
Length of tangent bp = 24 Cm
and op = 26 Cm
Thus
In the figure
if we draw a perpendicular from o on tangent bp to point y
we can say that
by = yp
Thus
yp = bp / 2
= 24/2
= 12 Cm
Thus in triangle oyp
op^2 = oy^2 + yp^2
Thus
oy^2 = 26^2 - 12^2
oy = 23 Cm
Length of Chord ab = 16 Cm
Length of tangent bp = 24 Cm
and op = 26 Cm
Thus
In the figure
if we draw a perpendicular from o on tangent bp to point y
we can say that
by = yp
Thus
yp = bp / 2
= 24/2
= 12 Cm
Thus in triangle oyp
op^2 = oy^2 + yp^2
Thus
oy^2 = 26^2 - 12^2
oy = 23 Cm
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