Ab is a chord of circle of radius 10cm.the chords subtends a right angle at the centre find the area of the minor segments .take ฯ=3.14
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Area of the sector of angle =∅/360 × лr² ⇒90/360 × 22/7 × 10 × 10
⇒78.5cmArea of ΔOAB = 1/2 × 10 × 10 [1/2 × base × hight] ⇒50cmarea of minor segment =area of the sector of angle - area of ΔOAB
⇒78.5 - 50
⇒28.5
⇒78.5cmArea of ΔOAB = 1/2 × 10 × 10 [1/2 × base × hight] ⇒50cmarea of minor segment =area of the sector of angle - area of ΔOAB
⇒78.5 - 50
⇒28.5
khushiism800:
soory for the arrangement
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