Question

ab is a chord of circle
with radius 8 cm
distance from the circle is 4 cm find the chord ​

Answer 1

Answer:

☃️QUESTION☃️

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• AB is a chord of circle with radius 8 cm. Distance from the circle is 4 cm. find the length of the chord .

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☃️ANSWER☃️

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✏️GIVEN✏️⠀

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• Radius of circle=8cm
• Diatance of chord from centre=4cm⠀

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✏️TO FIND✏️

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• Length of chord=???⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

✏️SOLUTION✏️⠀⠀

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Here,Radius=OA=OC=8cm

Distance of chord from centre=OB=4cm

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So, In triangle OAB

${OA}^{2}={OB}^{2}+{AB}^{2}$

$=>{8}^{2}={4}^{2}+{AB}^{2}$

$=>AB=\sqrt{64-16}$

$=>AB=\sqrt{48}$

$Hence,AB=4\sqrt{3}cm$

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Length of chord=AC

⠀⠀⠀⠀⠀=AB×2

⠀⠀⠀⠀⠀=$4\sqrt{3}×2</p><p>=8\sqrt{3}cm$

✈THEOREAM USED✈

• Perpendicular from the center of the circle to the chord bisects the chord.