Question

AB is a chord of the circle and AOC is its diameter such that angle ACB = 50°. If AT is the

tangent to the circle at the point A, then BAT is equal to

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Answer 1

Answer:

from the given figure we know a tangent is perpendicular to the circle

so ∠TAC=∠TAB+∠BAC=90 [equation 1]

now in triangle ABC ∠ABC=90 [since the triangle is in a semi circle]

∠ABC+∠BCA+∠CAB=180

therefore ∠CAB=180−90−50=40

so from equation 1 we get

∠TAB=90−∠BAC=90−40=50