Question

AB is a diameter of a circle. AH and BH are perpendiculars from A and B resp. to the tangent P. Prove that AH + BK = AB............PLS EXPLAIN WITH FIGURE AND FULL STEPS!!

Answer 1

Hello sis.,!! May this help you.,!! Except figure , rest all are ok

According to question
Let O be the center of the circle and join O to P
Thus OP = radius of the circle = r
we  are given that     AB =  diamete
So  AB / 2 = Radius = r = OP
Also   OP  = AH = BKSoAB / 2 = AHAB = 2 AHAB = AH + BK
Hence Proved

Answer 2

Answer:

According to question

Let O be the center of the circle and join O to P

Thus OP = radius of the circle = r

we  are given that     AB =  diamete

So  AB / 2 = Radius = r = OP

Also   OP  = AH = BKSoAB / 2 = AHAB = 2 AHAB = AH + BK

Hence Proved