Question

show that any positive integer is of the form3q, 3q+1, 3q+2

Answer 1

Hey.... I think this can be ur answer dear!!
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Let a be any positive integer an b be 3

So,
a = bq +r
Where r is bigger than or equal to 0
And smaller than b
So,

a=3q , 3q +1 and 3q+2....

So,any positive integer is of the form 3q, 3q+1, 3q+2...

Hence proved
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Hope it helps you dear ☺️☺️

Answer 2

Hi!!!!!!!

Let a be any positive integer and b=3

Since 0<r<3, the possible remainders are 0,1 and 2.

Then, by Euclid's algorithm a can be 3q or 3q+1 or 3q+2

Hope it hlpzzz.....

FOLLOW ME!!!!!