AB is a diameter of a circle. AH and BK are perpendicular from A and B respectively to the tangent at P. Prove that AH and BK is equals to AB.
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Answered by
280
SOLUTION:
[FIGURE IS IN THE ATTACHMENT]
Given:
AH and BK are perpendiculars drawn from A and B on tangent at P.
To Prove:AH + BK = AB
PROOF:
ABKH is a rectangle.(AH & BK are Perpendiculars.
AB = HK …..…….....(1)
[Opposite sides of rectangle are equal]
We know that, the lengths of tangents drawn from an external point to the circle are equal.
AH = HP ……............(2)
BK = PK ..….............(3)
Adding eq. (2) and (3),
AH + BK = HP + PK = HK
AH + BK = AB [from eq. (1)]
HOPE THIS WILL HELP YOU..
[FIGURE IS IN THE ATTACHMENT]
Given:
AH and BK are perpendiculars drawn from A and B on tangent at P.
To Prove:AH + BK = AB
PROOF:
ABKH is a rectangle.(AH & BK are Perpendiculars.
AB = HK …..…….....(1)
[Opposite sides of rectangle are equal]
We know that, the lengths of tangents drawn from an external point to the circle are equal.
AH = HP ……............(2)
BK = PK ..….............(3)
Adding eq. (2) and (3),
AH + BK = HP + PK = HK
AH + BK = AB [from eq. (1)]
HOPE THIS WILL HELP YOU..
Attachments:
![](https://hi-static.z-dn.net/files/df8/3cafbdd6daeb2874890ee482f37f16f4.png)
Answered by
166
see it is very very easy
Attachments:
![](https://hi-static.z-dn.net/files/dc7/22dcfd3f84c917fb71f6118b7530000c.jpg)
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