Question

AB is a diameter of a circle with centre O,C is point on the circle and angle OBC equal to 60 degree find angle OCA​

Answer 1

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AB is the diameter of circle with centre O.

< OBC :- 60°

< OCA :- ?

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< OBC :- 60°

AC = BC .......radius of circle

< OBC = < OAC (60°)

< ABC + < BCA + < CAO = 180°

60° + 60° + < ACB = 180°

120° + < ACB = 180°

< ACB = 60°

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< OCA = 1/2 <ACB .....{OC is the bisector of <ACB}

< OCA = 1/2×60

<OCA = 30°

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Answer 2

Step-by-step explanation:

Answer is here.

I have given all the data in my photo. So i dont think i should write here.