• AB is a diameter of a circle with centre P and radius 8.5 cm. Point C lies on a
semicircle. If BC = 8 cm, find AC.
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Answered by
9
Answer:
AC = 15 cm
Step-by-step explanation:
In this case, ΔACB is a right-angled triangle, right-angled at C.
(Reason: The diameter always subtends a right angle on the circle.)
By Pythagoras theorem,
(Length)² + (Height)² = (Hypotenuse)²
AC² + BC² = AB²
AC² + 64 = 289
AC² = 225
AC = √225 = 15 cm
Hence solved
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