Question

AB is a fixed line. state the locus of the point P so that AB² = AP² + BP².​

Answer 1

SOLUTION :-

so , AB² = AP² + BP²

hence, locus is the circle with diameter as AB.

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Answer 2

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Let P(x, y) be any point on the locus.

Given, PA + PB = 6, where coordinates of point A is (0, 2) and B is (0, – 2).

or PA = 6 – PB

Squaring both the sides.

Squaring both the sides

So, the locus of the point P is 9x2 + 5y2 – 45 = 0.