Question

AB is a line segment and line / is its perpendicular bisector. If a point P lines on /. show that p is equidistant from A and B. ​

Answer 1

Answer:

We have show ∆API congruent to ∆BPI

ok now

IP=IP....... common side

Angle PIA=Angle PIB ....both 90°

AI=BI...........PI is bisector

Therefore ∆API congruent to ∆BPI

now AP=BP......CPCT

Hence proved P is equidastant from A and B