AB is a line segment and line l is its perpendicular bisector. Show that every point on the line l is equidistant from A and B
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Answered by
7
firstly draw the figure like this
now let x be any point on line l
so in triangle XAO and triangle XBO
XO=XO (COMMON)
AO = OB ( BISECTOR )
ANGLE XOA= ANGLE XOB ( EACH 90 )
therefore triangle XAO and XBO
are congrent and by CPCT XB = XA
imples that every point on line l is equdistant from A and B
now let x be any point on line l
so in triangle XAO and triangle XBO
XO=XO (COMMON)
AO = OB ( BISECTOR )
ANGLE XOA= ANGLE XOB ( EACH 90 )
therefore triangle XAO and XBO
are congrent and by CPCT XB = XA
imples that every point on line l is equdistant from A and B
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welcm
if it helped plese mark me the brainlyest
thnx
Answered by
6
Answer:
Refer to the attachment_
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