Question

AB is a line segment and line L is its perpendicular bisector. if a pont P lines on L show that P is equidistant from A and B​

Answer 1

Step-by-step explanation:

Line l⊥AB and passes through C which is the midpoint of AB

To show that PA=PB

In △PCA and △PCB

AC=BC since C is the mid-point of AB

∠PCA=∠PCB=90

∘

(given)

PC=PC(common)

So,△PCA≅△PCB by SAS rule.

and so PA=PB as they are corresponding sides of congruent triangles.