Question

AB is a parallelogram. AB is produced to E so that BE = AB prove the ED bisects the ED bisects BC. With diagram

Answer 1

Answer:

As, AB=BE

B is mid point of AE

Consider △EAD

From midpoint Theorem

BM=

2

1

AD (AsAD∥BM) & B is mid point of AE

⇒=

2

1

BC (As AD = BC for parallelogram)

⇒ M is midpoint of BC

Hence ED bisects BC